2w^2-19w+42=(w-6^2)

Solution for 2w^2-19w+42=(w-6^2) equation:

2w^2-19w+42=(w-6^2)

We move all terms to the left:

2w^2-19w+42-((w-6^2))=0


We calculate terms in parentheses: -((w-6^2)), so:

(w-6^2)

We get rid of parentheses

w-6^2

We add all the numbers together, and all the variables

w-36

Back to the equation:

-(w-36)


We get rid of parentheses

2w^2-19w-w+36+42=0

We add all the numbers together, and all the variables

2w^2-20w+78=0

a = 2; b = -20; c = +78;
Δ = b2-4ac
Δ = -202-4·2·78
Δ = -224
Delta is less than zero, so there is no solution for the equation